Bioe339 Hw 8#4 Ans

dose 1.3 1.3 1.3 1.3 4.5 4.5 4.5 4.5 13.5 13.5 13.5 13.5 Negative Positive 73.61 130.69 118.01 140.2 26.95 53.23 59.57 53.23 -8.83 25.14 20.16 34.65 170.72 85.36 244.95 122.475 238.27 119.135 232.59 116.295 55.46 27.73 83.88 41.94 103.94 51.97 89.46 44.73 -44.63 -22.315 17.21 8.605 1.08 0.54 40.01 20.005 726.61 506.33 original 60.55083 42.19417 humble 1232.94 51.3725 SST 494.4842 6291.186 4440.49 7890.236 596.4829 3.448449 67.19081 3.448449 3624.401 688.1703 974.2514 279.6587 97.11 114.26 120.26 92.39 28.51 30.65 44.37 36.23 -35.8 -7.93 -19.08 5.36 dose 1 Dose 2 Dose 3 summarise bring Mean 886.53 110.8163 332.74 41.5925 13.67 1.70875 1232.94 SSA = SSB = Total Total mean (Xi-Xbar)^2 2091.873 3954.775 4745.419 1682.394 522.7168 429.4427 49.04201 229.3104 7599.132 3516.846 4963.625 2117.196 Sum 57255.221 SST 1011.269 1011.269 2022.538 SSAB= 19.08816 6.375625 47.61 19.0445 6.4009 47.3344 145.

8536 Assumption Norm all(prenominal)y distributed conception of discourse and has same discrepancy Random sample of surface 4 Hypothesis H0: Ai =0 for I = 1, 2, 3a HA: all Ai are non friction match to 0 H0: Bi =0 for I = 1, 2, 3b HA: all Bi are not pertain to 0 singular level of neuroprotection find out different levels of neuroprotection detected characteristic detected different levels detected  outpouring Statictic V.R. (A)= MSA/ MSE V.R.(B) = MSB/ MSE dissemination of runnel Statictic (A) df in numerator is 2 and denominator 6 (B) df in numerator is 1 and denominator 6 decision rule important=0.05 F1 =5.14 F2 =5.99 Calculation of quiz Statictic analysis of variance Source A breach B Block AB Block Treatment counterbalance Total SS SSA SSB SSAB SSTr SSE SST df 2 1 2 1 6 7 SS 48765.57 2022.538 145.8536 50933.96 6321.262 57255.22 MS VR 24382.78 7.7145299 2022.538 0.3199579 72.92679 50933.96 1053.544 8179.317 statistical conclusiveness 7.714 >5.14 Therefore the first nought hypothesis hindquarters be rejected 0.3199If you want to come up a bounteous essay, rate it on our website: Ordercustompaper.com

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